HBA #1
Do this assignment to get an easy hour by arrangement credit. First read the "LaTeX Tutorial" post to learn some basic LaTeX commands (LaTeX is a mathematical typesetting language that creates beautifully typeset mathematical documents).Next, reply to this post using some basic LaTeX commands to create the quadratic formula in "display style" as shown here:
$$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$$
Note: You can get the $\pm$ symbol with the LaTeX command \pm.
Don't forget to put your name in the post so I can give you credit.
That's all there is to it.
x=\frac{-b\pm\sqrt{b^2 - 4ac}}{2a} --Rod Hajaj
ReplyDeleteRod,
DeleteAll latex commands start with a \ symbol and must be between single or double dollar signs. Your post should display as:
$$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
$ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$ By Kaya Ota
ReplyDelete$$ \sum_{k=0}^{\infty}love_k $$
Delete$$x = \frac{-b\pm\sqrt{b^2-4ac}}
ReplyDelete{2a}$$
-Bryan Wolfe
Can't edit or fully remove comments. Wats up with that!
I'm not sure...maybe because you are not the author of the blog? I can fully remove comments.
Delete$$x = \frac{-b\pm\sqrt{b^2-4ac}} {2a}$$ -Aaron Tsang
ReplyDelete$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDelete$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ by Thoe Sin
ReplyDelete$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
ReplyDelete$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
ReplyDelete$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDeletePedram Madanchian
$$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$$
ReplyDelete$$x\;=\;\frac{-b\;\pm\;\sqrt{b^2\;-\;4ac}}{2a}$$
ReplyDeleteErnesto Lomeli
$$ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} $$
ReplyDelete-Vincent Chang
$$ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDelete$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDelete- Qiong Teng
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDeleteviliami taumoepeau
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDelete-Jasmine Flores
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteThis comment has been removed by the author.
ReplyDelete$$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDelete- Bhavin Tandel
This comment has been removed by the author.
ReplyDelete$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
ReplyDelete